Jaylin Williams finished among 10 best in this 2025-26 NBA award

In the latter half of Round 1, the league has begun to trickle out its award winners during the 2026 NBA playoffs. We saw another one announced on Tuesday as the Oklahoma City Thunder get a chance to kick up their feet and relax after another mundane Round 1 sweep. The Thunder had another one of their players featured in an award ballot.

Jaylin Williams finished in 10th place for the 2025-26 Twyman-Stokes Teammate of the Year trophy. New Orleans Pelicans ' DeAndre Jordan won the honor. Presented annually since 2012-13, the award recognizes the player deemed the league’s best teammate, based on selfless play, leadership and commitment to the team.

Williams was one of the dozen finalists for it. Each conference had six players in the race. Williams tallied 471 total voting points.

He had 25 first-place votes, 14 second-place votes, 11 third-place votes, 16 fourth-place votes and 20 fifth-place votes. For context, Jordan had 1,445 voting points. Runner-up Jrue Holiday finished with 1,437 voting points.