Will Smith hits go-ahead homer on his birthday

Mar 28, 2026; Los Angeles, California, USA; Los Angeles Dodgers catcher Will Smith (16) hits a two-run home run during the eighth inning against the Arizona Diamondbacks at Dodger Stadium. Mandatory Credit: Jayne Kamin-Oncea-Imagn Images | Jayne Kamin-Oncea-Imagn Images It’s not about how you start it; it’s about how you finish it. Following in the script of Friday’s win, this time with even more drama, the Dodgers waited to take command of the game for the first time in the bottom of the eighth inning.

Diamondbacks reliever Juan Morillo came in on the highest possible leverage spot, trying to protect a 2-1 lead with the top of the order up. Morillo retired Shohei Ohtani and Kyle Tucker and appeared in line to survive this gauntlet, but Mookie Betts and Will Smith had other plans. Betts walked on four pitches, and Morillo fed Smith one too many high fastballs until Smith caught the timing of one and knocked it out of the park for a go-ahead two-run bomb.

HAPPY BIRTHDAY, WILL SMITH! pic. twitter.

com/WTIuYcWJJy — Los Angeles Dodgers (@Dodgers) March 29, 2026 The birthday boy decided the game felt a tad too cliché, but you won’t hear anyone complaining in the home crowd. Smith, who hit 12 of his 17 home runs last season at Dodger Stadium, already has two in his home park in 2026. Before the Dodgers could find a way to take the lead in this game, they had to survive for a rather lengthy period despite very little offense, and that went through Tyler Glasnow.