New Headline: ATP Masters 250 Stakes Grand Slam Showdown: Federer vs. Nadal in Riviera Riviera Finals
Photo by Bradley Kanaris/Getty Images Medvedev and Sinner are set to renew their rivalry in the Indian Wells Final. Daniil Medvedev and Jannik Sinner will meet for the 16th time when they face off in the Indian Wells Open final. Both players have looked strong throughout the tournament, with Medvedev seeded second and Sinner coming in at No.
11. Medvedev reached the final by snapping Carlos Alcaraz’s winning run, earning his first victory over the Spaniard since the 2023 US Open. Sinner advanced with a straightforward win over Alexander Zverev, taking down the German in straight sets, 6-2, 6-4.
Sinner vs Medvedev: Head-to-head record Sinner has won each of their last five encounters, though, dating back to October last year. Before that, though, it was all one-way traffic as Medvedev won their first six matches on tour together. Photo by Tnani Badreddine/DeFodi Images/DeFodi via Getty Images Medvedev and Sinner are unbeaten ahead of the Indian Wells final The 2026 Indian Wells Open final brings together two players who haven’t dropped a set all tournament, something that hasn’t happened since 2015.
Sinner and Medvedev have both been in top form throughout the event, each moving through the draw without giving up a single set. Opta Ace notes that the last time this occurred was in 2015 when Roger Federer and Novak Djokovic reached the final unbeaten, with Djokovic eventually taking the title. Sinner reached the final with straight-set wins over Joao Fonseca, Learner Tien, and Alexander Zverev.
Medvedev’s path included victories over Alex Michelsen, defending champion Jack Draper, and Carlos Alcaraz. Looking back at Sinner and Medvedev’s last final meeting Sinner holds a strong record against Medvedev, having come out on top in seven of their past eight encounters. Medvedev won the first four matches between them on tour, but since Sinner’s breakthrough win in the 2023 Beijing final, he has only lost to the Russian once.